Atomic Structure

B.Sc. 1st Year Chemistry | CHE-101 | Tribhuvan University

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About This Chapter

Atomic structure explains how electrons are arranged in atoms and why atoms can absorb or emit definite amounts of energy. The chapter connects the early atomic models with the modern wave-mechanical description of electrons.

The important progression is: Rutherford model → Bohr model → de Broglie matter waves → Heisenberg uncertainty principle → Schrödinger wave mechanics.

For examination preparation, do not learn the equations separately from their meaning. You should be able to state the principle, write the equation, explain the symbols and interpret the result.

Study focus: This chapter is mainly built around atomic models, quantum numbers, orbitals, nodes, energy levels and basic numerical problems.

Chapter Contents

  1. Basic ideas of atomic structure
  2. Bohr atomic model
  3. Matter waves and de Broglie hypothesis
  4. Heisenberg uncertainty principle
  5. Wave-mechanical model and Schrödinger equation
  6. Wave function and probability density
  7. Radial and angular wave functions
  8. Radial distribution function
  9. Atomic orbitals and their shapes
  10. Nodes and nodal surfaces
  11. Quantum numbers
  12. Energy levels and electronic arrangement
  13. Worked numerical problems
  14. Important comparisons
  15. Chemistry and laboratory connections
  16. Common mistakes
  17. Practice yourself
  18. TU examination preparation
  19. Quick revision

1. Basic Ideas of Atomic Structure

An atom contains a small, dense nucleus surrounded by electrons. The nucleus contains positively charged protons and electrically neutral neutrons.

Atom: An atom is the smallest unit of an element that retains the chemical identity of that element.

Fundamental particles

Particle Charge Relative mass Location
Proton +1 Approximately 1 u Nucleus
Neutron 0 Approximately 1 u Nucleus
Electron -1 Approximately 1/1836 u Outside the nucleus

Atomic number

Atomic number is represented by Z. It is equal to the number of protons in the nucleus and identifies the element.

Z = number of protons For a neutral atom: number of electrons = Z

Mass number

Mass number is represented by A. It is the total number of protons and neutrons in the nucleus.

A = number of protons + number of neutrons Number of neutrons: N = A - Z

Example

Consider nitrogen written as:

¹⁴₇N

Therefore:

Isotopes

Isotopes are atoms of the same element having the same atomic number but different mass numbers because they contain different numbers of neutrons.

Example: ¹²C, ¹³C and ¹⁴C All have Z = 6 But their numbers of neutrons are different.

Quick Check

An atom has A = 23 and Z = 11. How many neutrons does it contain?

N = A - Z = 23 - 11 = 12 neutrons.

2. Bohr Atomic Model

Rutherford's nuclear model established the existence of a small positive nucleus. However, the classical model could not explain why an electron moving around the nucleus would not continuously lose energy.

Niels Bohr proposed that electrons can exist only in certain permitted energy states.

Postulates of Bohr's model

  1. Electrons can occupy certain permitted circular stationary orbits around the nucleus.
  2. An electron in an allowed stationary orbit does not continuously radiate energy.
  3. The angular momentum of an electron is quantized.
  4. Radiation is emitted or absorbed when an electron moves from one allowed energy state to another.

Quantization of angular momentum

mvr = nh/2π where: m = mass of electron v = velocity of electron r = radius of orbit n = principal quantum number h = Planck constant

Energy of hydrogen-like species

Eₙ = -13.6 Z²/n² eV For hydrogen: Z = 1 Therefore: Eₙ = -13.6/n² eV

The negative sign indicates that the electron has lower energy than the separated electron and nucleus at the ionization limit.

Radius of Bohr orbit

rₙ = a₀ n²/Z where: a₀ = Bohr radius ≈ 0.529 Å

Energy transition

When an electron changes from one allowed energy level to another, the energy difference is related to the frequency of radiation.

ΔE = E_final - E_initial For the magnitude of the photon energy: |ΔE| = hν Also: |ΔE| = hc/λ

Main limitation of Bohr's model

Important: Bohr's model explains the hydrogen spectrum and hydrogen-like one-electron species successfully, but it cannot adequately explain the spectra and detailed behaviour of multi-electron atoms.

It also treats electrons as moving in definite circular orbits, which is inconsistent with the later wave-mechanical description.

Quick Check

What happens to the energy of a hydrogen electron when n increases?

The energy becomes less negative and approaches zero as n increases.

3. Matter Waves and de Broglie Hypothesis

Louis de Broglie proposed that moving matter particles have an associated wavelength. This idea extended the wave-particle concept from radiation to matter.

de Broglie hypothesis: A moving particle has an associated wavelength given by: λ = h/p

de Broglie equation

λ = h/p Since: p = mv Therefore: λ = h/mv

Electron accelerated through a potential difference

If an electron is accelerated through a potential difference V, its kinetic energy is related to the accelerating potential.

eV = 1/2 mv² Therefore: λ = h/√(2meV)

Interpretation

Wavelength decreases when momentum increases. Electrons have very small mass, so their de Broglie wavelength can become comparable with atomic dimensions.

Connection with Bohr's model

If an electron behaves as a wave, a permitted circular orbit can be represented by a whole number of wavelengths fitting around the circumference.

2πr = nλ Substituting: λ = h/mv gives: 2πr = nh/mv Therefore: mvr = nh/2π

This reproduces Bohr's quantization condition and shows how the wave description provides a physical basis for the allowed-orbit condition.

Quick Check

If the momentum of a particle is doubled, what happens to its de Broglie wavelength?

Since λ = h/p, doubling momentum makes the wavelength half as large.

4. Heisenberg Uncertainty Principle

Werner Heisenberg showed that position and momentum of a microscopic particle cannot both be known with unlimited precision at the same time.

Uncertainty principle: The product of the uncertainties in position and momentum has a minimum limit:
Δx × Δp ≥ h/4π Since: Δp = mΔv Therefore: Δx × Δv ≥ h/(4πm)

Physical meaning

If the uncertainty in position is reduced, the minimum possible uncertainty in momentum increases. This is a fundamental property of quantum systems, not simply a defect of laboratory instruments.

Do not write: "Position and momentum cannot be measured."

A better statement is: "The uncertainties in position and momentum are related by a fundamental inequality, so they cannot both be made arbitrarily small simultaneously."

5. Wave-Mechanical Model and Schrödinger Equation

The wave-mechanical model does not describe an electron as following a fixed circular path. Instead, the electron is described by a wave function.

Erwin Schrödinger developed the wave equation used to obtain the allowed quantum states and energies of a system.

Time-independent Schrödinger equation

Ĥψ = Eψ Expanded form: -(h²/8π²m)∇²ψ + Vψ = Eψ or: ∇²ψ + (8π²m/h²)(E - V)ψ = 0

Meaning of important symbols

Symbol Meaning
ψ Wave function
|ψ|² Probability density
Ĥ Hamiltonian operator
E Allowed energy
V Potential energy
m Mass of the particle
∇² Laplacian operator

What do the solutions provide?

Solving the Schrödinger equation gives allowed wave functions and their corresponding energy values. The mathematical solutions are associated with quantum numbers, atomic orbitals and the probability distribution of the electron.

Important connection

The quantum numbers used later in this chapter are not arbitrary labels. They arise from the mathematical conditions imposed on acceptable solutions of the wave equation.

6. Wave Function and Probability Density

The wave function, represented by ψ, is a mathematical function that describes the quantum state of an electron.

Important distinction: ψ itself is not the probability density.

The probability density is: |ψ|²

Probability of finding an electron

For a small volume dτ: Probability = |ψ|² dτ For a normalized wave function: ∫ |ψ|² dτ = 1

A larger value of |ψ|² at a particular point means a higher probability density there. It does not mean that the electron is permanently located at that point.

Conditions for an acceptable wave function

A physically acceptable wave function should be finite, single-valued and continuous in the appropriate region.

Common mistake: Do not write: "ψ² gives the exact position of the electron." Instead, write: "|ψ|² represents probability density."

7. Radial and Angular Wave Functions

For a hydrogen-like atom, the wave function can be separated into a radial part and an angular part.

ψ(r, θ, φ) = R(r)Y(θ, φ) where: R(r) = radial wave function Y(θ, φ) = angular wave function

Radial wave function

The radial part depends on the distance r from the nucleus. It describes how the wave function changes with distance.

Angular wave function

The angular part depends on direction and is responsible for the directional characteristics and shapes of orbitals.

Feature Radial part Angular part
Main variable Distance from nucleus Direction / angles
Related to Radial behaviour Orbital shape and orientation
Nodes Radial nodes Angular nodes

8. Radial Distribution Function

Probability density and radial probability are related but are not the same quantity.

Probability density

Probability density = |ψ|²

It describes probability per unit volume at a particular point or region of space.

Radial distribution

For a hydrogen-like orbital, if the wave function is written as ψ = R(r)Y(θ,φ), the radial probability distribution is proportional to the probability of finding the electron in a spherical shell at distance r.

P(r) = 4πr²|R(r)|² for a normalized hydrogenic orbital.

The factor 4πr² represents the volume of a spherical shell of radius r and unit thickness.

Why can the radial distribution have a maximum?

Close to the nucleus the spherical shell has very small volume. As r increases, the shell volume increases. The radial distribution therefore depends on both the radial wave function and the available spherical volume.

Radial
probability
    |
    |             /\
    |            /  \
    |           /    \
    |          /      \
    |_________/        \________
    |
    +-----------------------------> r
               distance

The number and position of maxima depend on the orbital.

Radial nodes

A radial node is a spherical region at a particular distance from the nucleus where the radial wave function becomes zero.

Number of radial nodes: n - l - 1

9. Atomic Orbitals and Their Shapes

An atomic orbital is a one-electron quantum state described by a wave function. The square of its magnitude, |ψ|², gives the probability density associated with that state.

Orbit vs orbital: A Bohr orbit is a definite circular path in the old model. An orbital is a quantum-mechanical state with a spatial probability distribution.

s orbital

For an s orbital, l = 0. It is spherically symmetric around the nucleus.

             . . . . . .
          .               .
        .                   .
       .         ●           .
        .                   .
          .               .
             . . . . . .

              1s orbital

The point represents the nucleus. The orbital itself is represented as a three-dimensional spherical region.

p orbitals

For p orbitals, l = 1. There are three p orbitals because mₗ can have three values: -1, 0 and +1.

They are commonly represented as pₓ, pᵧ and p𝓏 and have two lobes separated by an angular nodal plane.

              p orbital

                  ●
                  |
                  |
               ___|___
             /         \
            /           \
           /             \
          ●               ●
           \             /
            \           /
             \_________/

        Two lobes separated by
        an angular nodal plane

d orbitals

For d orbitals, l = 2 and five orbitals are possible.

Four d orbitals are commonly represented with four lobes, while d𝓏² has two lobes along the z-axis together with a toroidal region around the nucleus.

Number of orbitals in a subshell

Number of orbitals = 2l + 1 s: l = 0 → 1 orbital p: l = 1 → 3 orbitals d: l = 2 → 5 orbitals f: l = 3 → 7 orbitals Maximum electrons in a subshell: 2(2l + 1)
Subshell l Number of orbitals Maximum electrons
s 0 1 2
p 1 3 6
d 2 5 10
f 3 7 14

10. Nodes and Nodal Surfaces

A node is a region in which the wave function is zero and therefore the probability density is zero.

Radial nodes

Radial nodes occur at particular distances from the nucleus and are spherical surfaces.

Angular nodes

Angular nodes are surfaces determined by the angular part of the wave function. Depending on the orbital, they can be planes or other angular nodal surfaces.

Total nodes = n - 1 Angular nodes = l Radial nodes = n - l - 1

Examples

Orbital n l Total nodes Angular nodes Radial nodes
1s 1 0 0 0 0
2s 2 0 1 0 1
2p 2 1 1 1 0
3s 3 0 2 0 2
3p 3 1 2 1 1
3d 3 2 2 2 0
4d 4 2 3 2 1
Easy calculation method: For 4d:

Total nodes = 4 - 1 = 3
Angular nodes = l = 2
Radial nodes = 3 - 2 = 1

11. Quantum Numbers

Four quantum numbers are used to specify the quantum state of an electron in an atom.

Quantum number Symbol Allowed values Describes
Principal n 1, 2, 3, ... Shell, size and main energy level
Azimuthal l 0 to n - 1 Subshell and orbital shape
Magnetic mₗ -l to +l Orbital orientation
Spin mₛ +1/2 or -1/2 Electron spin state

Principal quantum number (n)

The principal quantum number identifies the main shell and is associated with the size and main energy level.

n = 1, 2, 3, 4, ... n = 1 → K shell n = 2 → L shell n = 3 → M shell n = 4 → N shell

Azimuthal quantum number (l)

l = 0, 1, 2, ... , n - 1 l = 0 → s l = 1 → p l = 2 → d l = 3 → f

Magnetic quantum number (mₗ)

mₗ = -l, ..., 0, ..., +l Number of possible mₗ values: 2l + 1

Spin quantum number (mₛ)

The spin quantum number has two possible values.

mₛ = +1/2 or mₛ = -1/2
Important: Electron spin is an intrinsic quantum property. It should not be interpreted simply as the electron being a tiny ball physically rotating like a planet.

Quantum-number validity test

Consider:

n = 3 l = 2 mₗ = -1 mₛ = +1/2

This is valid because:

Now consider:

n = 2 l = 2

This is invalid because for n = 2, l can only be 0 or 1.

Quick Check

Is n = 4, l = 3, mₗ = -2, mₛ = +1/2 a valid set?

Yes. For n = 4, l may be 0, 1, 2 or 3. For l = 3, mₗ may range from -3 to +3. The spin value is also allowed.

12. Energy Levels and Electronic Arrangement

Electrons occupy allowed quantum states. For a hydrogen atom, the energy depends on the principal quantum number n. In multi-electron atoms, electron-electron repulsion and shielding affect orbital energies.

Hydrogen-like energy levels

Eₙ = -13.6 Z²/n² eV
Energy
  ↑

   0 eV       ─────────────── n = ∞
               ionization limit

  -0.85 eV    ─────────────── n = 4

  -1.51 eV    ─────────────── n = 3

  -3.40 eV    ─────────────── n = 2

 -13.60 eV    ─────────────── n = 1

               lowest energy

Ground state

The lowest-energy state of an atom is called its ground state.

Excited state

When an electron absorbs an appropriate amount of energy and moves to a higher allowed state, the atom is in an excited state.

Emission of radiation

When an electron returns to a lower energy state, the energy difference can be released as electromagnetic radiation.

ΔE = hν ΔE = hc/λ Therefore: ν = ΔE/h λ = hc/ΔE

Hydrogen spectrum

Hydrogen produces discrete spectral lines because only specific energy transitions are allowed.

1/λ = RZ²(1/n₁² - 1/n₂²) where: n₂ > n₁ R = Rydberg constant
Series Final level Region
Lyman n = 1 Ultraviolet
Balmer n = 2 Visible / near ultraviolet
Paschen n = 3 Infrared
Brackett n = 4 Infrared
Pfund n = 5 Infrared

13. Worked Numerical Problems

For numerical questions, use the sequence: Given → Formula → Substitution → Calculation → Unit → Meaning of answer.

Numerical 1: de Broglie wavelength

Calculate the de Broglie wavelength of an electron moving with a velocity of 2.00 × 10⁶ m/s.

Given:
m = 9.11 × 10⁻³¹ kg
v = 2.00 × 10⁶ m/s
h = 6.626 × 10⁻³⁴ J s
Formula:
λ = h/mv
Substitution:
λ = (6.626 × 10⁻³⁴) / [(9.11 × 10⁻³¹)(2.00 × 10⁶)]
λ ≈ 3.64 × 10⁻¹⁰ m
Answer: λ ≈ 3.64 × 10⁻¹⁰ m
Interpretation: The wavelength is comparable with atomic dimensions, so the wave nature of electrons is important at the atomic scale.

Numerical 2: Energy of hydrogen electron

Calculate the energy of an electron in the second energy level of hydrogen.

Given:
Z = 1
n = 2
Formula:
Eₙ = -13.6Z²/n² eV
Substitution:
E₂ = -13.6(1)²/(2)²
E₂ = -13.6/4
E₂ = -3.40 eV
Answer: E₂ = -3.40 eV
Interpretation: The negative value indicates a bound state. The n = 2 electron is less tightly bound than the electron in n = 1.

Numerical 3: Radial nodes in 4p

Determine the number of radial nodes in a 4p orbital.

Given:
n = 4
l = 1 for p
Formula:
Radial nodes = n - l - 1
= 4 - 1 - 1
= 2
Answer: 4p has 2 radial nodes.

Numerical 4: Nodes in 4d

Determine the total, angular and radial nodes in a 4d orbital.

Given:
n = 4
l = 2 for d
Total nodes:
n - 1 = 4 - 1 = 3
Angular nodes:
l = 2
Radial nodes:
n - l - 1 = 4 - 2 - 1 = 1
Answer: Total = 3, Angular = 2, Radial = 1.

Numerical 5: Number of orbitals in a d subshell

For d: l = 2
Number of orbitals = 2l + 1
= 2(2) + 1
= 5
Answer: A d subshell contains 5 orbitals.
Further conclusion: Each orbital can hold two electrons, so the maximum number of electrons in a d subshell is 10.

Numerical 6: Minimum uncertainty in velocity

An electron has an uncertainty in position of 1.0 × 10⁻¹⁰ m. Estimate the minimum uncertainty in its velocity.

Given:
Δx = 1.0 × 10⁻¹⁰ m
m = 9.11 × 10⁻³¹ kg
h = 6.626 × 10⁻³⁴ J s
Formula:
ΔxΔv ≥ h/(4πm)
Therefore:
Δv ≥ h/(4πmΔx)
Substitution gives approximately:
Δv ≥ 5.79 × 10⁵ m/s
Approximate minimum uncertainty: Δv ≈ 5.8 × 10⁵ m/s
Interpretation: At atomic dimensions, even a small uncertainty in position can correspond to a substantial uncertainty in velocity.

Numerical 7: Energy of hydrogen at n = 3

Formula:
Eₙ = -13.6/n² eV
For n = 3:
E₃ = -13.6/9
E₃ ≈ -1.51 eV
Answer: E₃ ≈ -1.51 eV

14. Important Comparisons

Orbit and orbital

Orbit Orbital
Associated with Bohr's model. Associated with quantum mechanics.
Represents a definite path. Represents a quantum state described by a wave function.
Electron is treated as moving along the path. |ψ|² gives probability density.
Does not describe electron probability distribution. Describes spatial probability distribution.

Probability density and radial probability

Probability density Radial probability distribution
|ψ|² 4πr²|R(r)|² for a hydrogenic orbital
Probability per unit volume. Probability associated with a spherical shell.
Does not include shell-volume factor separately. Includes the 4πr² volume factor.

Bohr model and wave-mechanical model

Bohr model Wave-mechanical model
Electrons occupy fixed allowed orbits. Electrons are described by wave functions.
Angular momentum is quantized directly. Allowed states arise from quantum-mechanical solutions.
Useful for hydrogen-like systems. Provides the basis for modern atomic structure.
Does not adequately explain multi-electron atoms. Accounts for quantum numbers and orbitals.

15. Chemistry and Laboratory Connections

Atomic structure becomes useful beyond this chapter because electron energy and electronic arrangement help explain several later areas of chemistry.

Spectroscopy

Atoms and molecules can interact with electromagnetic radiation. Absorption or emission at particular energies can provide information about the species being studied.

Flame and emission observations

Characteristic colours produced by some metal ions are associated with electronic transitions between allowed energy states.

Periodic properties

Electron arrangement helps explain trends such as atomic size, ionization energy and electronegativity.

Chemical bonding

The concept of atomic orbitals is important for understanding orbital overlap, molecular orbitals, hybridization and bond formation in later chemistry topics.

Analytical chemistry

Many analytical methods depend on the interaction of matter with electromagnetic radiation. The detailed instruments differ, but the underlying ideas of energy levels and transitions connect back to atomic structure.

A useful way to connect the chapter

Atomic structure → electronic arrangement → energy differences → interaction with radiation → measurable spectral information.

16. Common Mistakes Students Make

  1. Orbit and orbital are different. Do not use the two terms interchangeably.
  2. ψ is not probability density. Probability density is |ψ|².
  3. Radial probability is not simply |ψ|². The spherical volume factor must be considered.
  4. Do not remove the negative sign from hydrogen energy. The negative value indicates a bound state.
  5. For n = 3, l cannot be 3. Allowed l values are 0, 1 and 2.
  6. A p subshell contains three orbitals, not three electrons. Each orbital can hold two electrons.
  7. Do not confuse total nodes with radial nodes. Total nodes = n - 1, while radial nodes = n - l - 1.
  8. Do not treat the uncertainty principle as an instrument problem. It is a fundamental quantum-mechanical relation.
  9. Check all four quantum numbers. One invalid value makes the complete set invalid.
  10. Do not skip units in numerical problems. Units often help identify calculation mistakes.
  11. Do not write only equations in a long-answer question. Explain what the equations mean.
  12. Do not treat an excited electron as permanently remaining in the excited state. Excited states can return to lower-energy states with energy release.

17. Practice Yourself

Try these questions without looking at the answers above. For numerical problems, show all working steps.

Concept questions

  1. Define atomic number and mass number.
  2. State the main postulates of Bohr's atomic model.
  3. Why was the Bohr model unable to explain all atomic spectra?
  4. State de Broglie's matter-wave hypothesis.
  5. State Heisenberg's uncertainty principle.
  6. What is the physical significance of |ψ|²?
  7. What is an atomic orbital?
  8. Define radial node and angular node.
  9. State the four quantum numbers.
  10. Explain why the hydrogen spectrum consists of discrete lines.

Numerical and application questions

  1. Calculate the energy of hydrogen in n = 4.
  2. Calculate the de Broglie wavelength of an electron when its velocity is given.
  3. Determine the number of radial nodes in a 5p orbital.
  4. Determine total, radial and angular nodes in a 5d orbital.
  5. How many orbitals and electrons are present in an f subshell?
  6. Check whether n = 3, l = 2, mₗ = +3, mₛ = -1/2 is valid.
  7. Check whether n = 4, l = 1, mₗ = 0, mₛ = +1/2 is valid.
Self-check: If you can obtain a numerical answer but cannot explain what the result means physically, review the concept behind the equation.

18. TU Examination Preparation

Atomic Structure contains definitions, explanations, equations, diagrams and numerical problems. The length of the answer should match the marks available.

2-mark preparation

5-mark preparation

10-mark preparation

A good 10-mark answer should normally contain:
  1. A short introduction or definition.
  2. The relevant theory or principle.
  3. Main postulates or important points.
  4. Equations with symbols explained.
  5. A suitable diagram where required.
  6. Explanation of the physical meaning.
  7. Limitations or significance where appropriate.
  8. A short concluding statement.

Answer structure by marks

Marks What to include
2 marks Definition, principle, formula or two clear points.
5 marks Definition + explanation + equation / example / small diagram where useful.
10 marks Introduction + theory + detailed explanation + equations + diagram / derivation + significance or limitation.

19. Quick Revision

Essential equations and facts

  • Atomic number = number of protons.
  • Mass number = protons + neutrons.
  • N = A - Z.
  • Bohr angular momentum: mvr = nh/2π.
  • Hydrogen-like energy: Eₙ = -13.6Z²/n² eV.
  • Bohr radius: rₙ = a₀n²/Z.
  • de Broglie wavelength: λ = h/mv.
  • Uncertainty: ΔxΔp ≥ h/4π.
  • Schrödinger equation: Ĥψ = Eψ.
  • Probability density: |ψ|².
  • Radial distribution: 4πr²|R(r)|².
  • Total nodes: n - 1.
  • Angular nodes: l.
  • Radial nodes: n - l - 1.
  • Orbitals in a subshell: 2l + 1.
  • Maximum electrons in a subshell: 2(2l + 1).
  • s, p, d and f correspond to l = 0, 1, 2 and 3.

Four quantum numbers at a glance

n Shell, size and main energy level
l Subshell, shape and angular nodes
mₗ Orbital orientation
mₛ Electron spin state

Node shortcut

Total nodes = n - 1 Angular nodes = l Radial nodes = n - l - 1

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